Cooling a cup of coffee with help of a spoon(physics.stackexchange.com)
physics.stackexchange.com
Cooling a cup of coffee with help of a spoon
http://physics.stackexchange.com/questions/5265/cooling-a-cup-of-coffee-with-help-of-a-spoon
20 comments
It won't be a fixed "10 degrees". More like dt = (T_cup - T_room) x cooling factor.
I'll leave it as an exercise, as to what 10 pours will do, but it won't freeze the water; as I don't remember how to solve it and I don't have a piece of paper handy.
And that's not accounting for the specific heat in the state change.
I'll leave it as an exercise, as to what 10 pours will do, but it won't freeze the water; as I don't remember how to solve it and I don't have a piece of paper handy.
And that's not accounting for the specific heat in the state change.
Entropy is logarithmic with respect to degrees of freedom, and since degrees of freedom is (usually but not always) proportional to the energy of the system, the temperatures of the tea and of the room will approach each other faster when the difference between them is greater, but the heat exchange will slow down when the temperatures are similar.
EDIT I meant to say that entropy is proportional to degrees of freedom, which is logarithmically related to heat energy (except in some weird cases). Anyway, the conclusion was right :-)
EDIT I meant to say that entropy is proportional to degrees of freedom, which is logarithmically related to heat energy (except in some weird cases). Anyway, the conclusion was right :-)
This is the traditional way of serving coffee in south India: http://farm4.static.flickr.com/3499/3281237995_091cdeac67.jp.... Basically, you get a cup and a bowl to pour it back and forth with.
I also remember my grandfather using saucering to cool hot tea down, I finally have an explanation for why it works.
I wonder why the practice went out of fashion. Do paper doilies send a signal that the saucer is not to be used to hold liquids?
I wonder why the practice went out of fashion. Do paper doilies send a signal that the saucer is not to be used to hold liquids?
From reading the Laura Ingalls Wilder books, when I was a young'n, I remember that 'saucering' was considered rural, unrefined behavior. That kind of thing goes out quick; I bet none of the Silver Screen movie stars were seen saucering their tea.
I always stir my coffee in a random way so that you see turbulent movement in the cup as opposed to the whirlpool you get from moving the spoon in smooth circles.
My intuition tells me that this should give more efficient cooling. I basically have nothing to back this up. Thinking about it, it probably makes more sense for dissolving the sugar than cooling the coffee.
My intuition tells me that this should give more efficient cooling. I basically have nothing to back this up. Thinking about it, it probably makes more sense for dissolving the sugar than cooling the coffee.
Your aim is to make sure that every bit of the coffee eventually makes it to the surface (so that the highest-energy molecules there can escape and cause cooling). If you stir regularly then (roughly) each bit of the coffee just moves in a circle, and parts that start out below the surface stay below the surface. If you stir it at random, then (this is probably a theorem, if you define "random" with a bit of care, and it probably doesn't require all that much randomness) any portion of the coffee ends up eventually at any given place.
So I think your intuition is doing pretty well.
So I think your intuition is doing pretty well.
Surely there are some regular motions which could be approximated using a spoon which would more efficiently move the hottest parts of a liquid to the surface than random turbulence? My intuition says sliding the spoon down the side of the mug, then turning the flat side upward and lifting it in the middle of the mug would be one such more efficient motion.
Does anybody have a supercomputing cluster we could use to run an optimizing search across a whole bunch of fluid flow simulations?
Does anybody have a supercomputing cluster we could use to run an optimizing search across a whole bunch of fluid flow simulations?
>My intuition says sliding the spoon down the side of the mug, then turning the flat side upward and lifting it in the middle of the mug would be one such more efficient motion.
You're still going to be getting laminar flow unless you're lifting fast enough to eject the tea from the cup (which I assume is contrary to the rules). I use a forward and backward motion going from low down at one side to high up at the other (especially when stirring hot soup for my little nearly 2yo) - I'm trying to produce a ragged (turbulent) collapsing void of air, maximising the surface area exposed particularly in producing as much turbulence as possible at the surface. One tends to get spiralling voids at either edge of the spoon.
I wonder if you can stir fast enough to produce cavitation and what effect that would have on the results.
Also can I design my own spoon to use?
-
http://en.wikipedia.org/wiki/Cavitation
You're still going to be getting laminar flow unless you're lifting fast enough to eject the tea from the cup (which I assume is contrary to the rules). I use a forward and backward motion going from low down at one side to high up at the other (especially when stirring hot soup for my little nearly 2yo) - I'm trying to produce a ragged (turbulent) collapsing void of air, maximising the surface area exposed particularly in producing as much turbulence as possible at the surface. One tends to get spiralling voids at either edge of the spoon.
I wonder if you can stir fast enough to produce cavitation and what effect that would have on the results.
Also can I design my own spoon to use?
-
http://en.wikipedia.org/wiki/Cavitation
I got one, but unfortunately it's still working on the milk-or-tea-first conundrum.
>milk-or-tea-first
Ahhhhh, the one debate more divisive than emacs-or-vim.
Ahhhhh, the one debate more divisive than emacs-or-vim.
Right, what I remember from Thermo II 20 yrs ago is that heat transfer in turbulent flow is higher than in laminar flow. Heat transfer is basically deltaT * someFactor, with someFactor depending on a ton of parameters. One of them is whether it's laminar or turbulent.
Someone on physics.stackexchange already mentioned that we should probably ask chemists. IIRC, the most commonly used stirring method in industry is, basically, figures-of-8.
I think that the explanation is wrong (or at least it is a oversimplification.)
The main problem is that the explanation ignores completely the air. Static air is a good isolator, therefore much of the heat must be transported by thermal convection or forced convection (blowing). If the air doesn't move, it wouldn't be useful to make each part of the coffee visit the surface.
The second problem is that the it says that most of the heat is lost by evaporation of the water molecules (latent evaporation heat). I think that this is true when the temperature is over 195 F/90 C. But when the water is cooler I think that thermal conduction is more important, and it is not related to the "high-kinetic-energy outlier water molecules". And also some heat is lost by the floor and walls of the cup, but I think that most of the heat is lost by the surface. [More details in "experiment" bellow.]
The third problem is more an oversimplification. It is incorrect imagine that some of the molecules of the water are "high-kinetic-energy outlier". Let imagine that we mentally "paint" the fast molecules at initial time. Very soon these molecules will bounce with other molecules and change their velocity, so a few instants later the fast molecules will be other molecules. To estimate the time that we have to wait until the fast molecules bounce we can use the "mean free time". This time is useful in a gas where the molecules are far apart, and for air in usual conditions it is ~5E-10seg. Obviously water is not a gas, but the molecules are more close together, so this the time we should wait is much smaller. But the time that a drop of water needs to go from the bottom to the top of the cup is ~.1 seg (rough estimation). So the molecules have time to bounce and bounce. Moreover, while the drop is traveling though the surface the molecules have time to bounce and reach thermal equilibrium after some of then evaporate. So I think that a macroscopic model that only consider the temperature should work.
[experiment]
A few yeas ago, I worked at a school and we need an experiment for a physic olympiad. We measure the cooling of a plastic cup of water in different conditions. The idea was that the temperature follow a law like:
Really tau is not constant. When the temperature if below 195 F/90 C the value of tau is almost constant and the graphic of the log is a nice line.
But when the water is hotter tau is not constant, the bigger the temperature, the bigger is tau (IIRC perhaps like twice the cold value). So the graphic of the log is curved and the water cooled faster than expected.
When the temperature if above 195 F/90 C something strange was happening. Looking at the cups we see that above that temperature there was a lot of steam over the cups and bellow that temperature the seam almost disappear. Looking at the graphics of the vapor pressure of water we saw that above 195 F/90 C the vapor pressure is bigger than the value bellow 195 F/90 C. So we expect to have a lot of evaporation when the water is hot and few evaporation when it is cold.
So the conclusion was that when the water is cold most of the heat is exchanged by conduction and convection, but when the water is hotter the evaporation is and additional important part of the cooling effects.
Note 1: We did some additional experiments that are consistent with this explanation, but perhaps there is something we forgot to check.
Note 2: The change between the "hot" and "cold" water above and bellow 195 F/90 C was not sharp. While the water was cooling the steam get thiner softly, tau get lower softly and the vapor pressure gets null softly. So the number 195 F/90 C is only an approximation. (And it was a few years ago.)
Note 3: Heat flow is difficult to modelate in paper, so better measure it experimentally. "In theory, practice is the same as theory. In practice, it differs."
The main problem is that the explanation ignores completely the air. Static air is a good isolator, therefore much of the heat must be transported by thermal convection or forced convection (blowing). If the air doesn't move, it wouldn't be useful to make each part of the coffee visit the surface.
The second problem is that the it says that most of the heat is lost by evaporation of the water molecules (latent evaporation heat). I think that this is true when the temperature is over 195 F/90 C. But when the water is cooler I think that thermal conduction is more important, and it is not related to the "high-kinetic-energy outlier water molecules". And also some heat is lost by the floor and walls of the cup, but I think that most of the heat is lost by the surface. [More details in "experiment" bellow.]
The third problem is more an oversimplification. It is incorrect imagine that some of the molecules of the water are "high-kinetic-energy outlier". Let imagine that we mentally "paint" the fast molecules at initial time. Very soon these molecules will bounce with other molecules and change their velocity, so a few instants later the fast molecules will be other molecules. To estimate the time that we have to wait until the fast molecules bounce we can use the "mean free time". This time is useful in a gas where the molecules are far apart, and for air in usual conditions it is ~5E-10seg. Obviously water is not a gas, but the molecules are more close together, so this the time we should wait is much smaller. But the time that a drop of water needs to go from the bottom to the top of the cup is ~.1 seg (rough estimation). So the molecules have time to bounce and bounce. Moreover, while the drop is traveling though the surface the molecules have time to bounce and reach thermal equilibrium after some of then evaporate. So I think that a macroscopic model that only consider the temperature should work.
[experiment]
A few yeas ago, I worked at a school and we need an experiment for a physic olympiad. We measure the cooling of a plastic cup of water in different conditions. The idea was that the temperature follow a law like:
Temp = Constant * exp(-time/tau) + Temp_external
log(Temp-Temp_external) = - time/tau + Konstant
Really tau is not constant. When the temperature if below 195 F/90 C the value of tau is almost constant and the graphic of the log is a nice line.
But when the water is hotter tau is not constant, the bigger the temperature, the bigger is tau (IIRC perhaps like twice the cold value). So the graphic of the log is curved and the water cooled faster than expected.
When the temperature if above 195 F/90 C something strange was happening. Looking at the cups we see that above that temperature there was a lot of steam over the cups and bellow that temperature the seam almost disappear. Looking at the graphics of the vapor pressure of water we saw that above 195 F/90 C the vapor pressure is bigger than the value bellow 195 F/90 C. So we expect to have a lot of evaporation when the water is hot and few evaporation when it is cold.
So the conclusion was that when the water is cold most of the heat is exchanged by conduction and convection, but when the water is hotter the evaporation is and additional important part of the cooling effects.
Note 1: We did some additional experiments that are consistent with this explanation, but perhaps there is something we forgot to check.
Note 2: The change between the "hot" and "cold" water above and bellow 195 F/90 C was not sharp. While the water was cooling the steam get thiner softly, tau get lower softly and the vapor pressure gets null softly. So the number 195 F/90 C is only an approximation. (And it was a few years ago.)
Note 3: Heat flow is difficult to modelate in paper, so better measure it experimentally. "In theory, practice is the same as theory. In practice, it differs."
Reminds me of a correction I sent to The Straight Dope many years ago: http://www.straightdope.com/columns/read/851/why-do-you-blow...
The indian drink stall sellers in Malaysia and Singapore have a good way to cool it down. It is called Teh Tarik
Picture here http://3.bp.blogspot.com/_0o2-S1p2MUo/Sm-YjNyRfpI/AAAAAAAAAd...
Description of what it is here http://en.wikipedia.org/wiki/Teh_tarik
Edit : Found a video of it here http://www.youtube.com/watch?v=WPuIybnQemc
Picture here http://3.bp.blogspot.com/_0o2-S1p2MUo/Sm-YjNyRfpI/AAAAAAAAAd...
Description of what it is here http://en.wikipedia.org/wiki/Teh_tarik
Edit : Found a video of it here http://www.youtube.com/watch?v=WPuIybnQemc
Similarly I've often wondered if it results in hotter coffee to mix your milk with the coffee when it goes into the thermos, rather than when it comes out. I'm pretty sure it is better to do it this way - my reasoning is that the hotter black coffee, because of a greater temperature difference with the surroundings, loses heat more rapidly through the thermos walls than the milk + coffee mixture. But I'm unsure how significant the effect is. Perhaps I'll measure it some time.
Yeah, that's interesting. I always do it the same way as you, but I decided to do a quick analytical calculation. I wrote it up here:
http://maxbrunsfeld.wordpress.com/2011/02/17/on-the-mixing-o...
my result agrees with your intuition.
http://maxbrunsfeld.wordpress.com/2011/02/17/on-the-mixing-o...
my result agrees with your intuition.
[deleted]
This is related to the phenomena that tea leaves tend to group in center of cup when you stir it with spoon.
Due to centrifugal forces the level of water near the border is higher that at the center so the water start to flow from borders to center at the bottom of the cup.
This speed up heat exchange as the water gets constantly mixed in addition of usual thermal exchange flow.
Due to centrifugal forces the level of water near the border is higher that at the center so the water start to flow from borders to center at the bottom of the cup.
This speed up heat exchange as the water gets constantly mixed in addition of usual thermal exchange flow.
I remember similar physics puzzle from high school days. Given a cup of hot tea and few spoons of sugar how does one go about sweetening the tea so that it would cool off the most in the process.
First, remove your sugar crystals from the thermos of liquid nitrogen...
Should you crush the sugar crystals (to promote rapid cooling) or should you use the largest possible crystals so there are more bonds to be broken?
I'm going to guess that there's a sweet spot in there somewhere; a priori it seems you want the maximum size that will dissolve completely.
I'm going to guess that there's a sweet spot in there somewhere; a priori it seems you want the maximum size that will dissolve completely.
If I remember the answer correctly, it went something like this. Dump all sugar into the tea at once and wait for the temperature to settle. Now split sugar in two halves, dissolve first half, wait for the temperature to stabilize, dissolve second half. Through math it worked out that the second method cooled the tea more. So the answer was to go with the infinitely small pieces of sugar :)
> This is why physicists need to talk to chemists once in a while.
Reminded-me of this xkcd strip: http://xkcd.com/435/
Reminded-me of this xkcd strip: http://xkcd.com/435/
I didn't understand that comment... was he insinuating physicists don't know thermodynamics? The original question is pretty basic.
I think he was saying that although physicists generally understand the principles involved, a chemist might have a better sense of the relative magnitudes of the different effects that come into play in cooling a solution, since chemists have to perform this task routinely.
I suppose, but any physicist worth anything should be able to remember enough high school chemistry to deduce the answer.
Fluid dynamics aren't exactly high school chemistry...
Feynman would get a cup of coffee, a spoon and a thermometer.
Why the downvotes? I usually don't like oneliners and reference to Feynman/Einstein, but I think that this comment has an important point. I will try to expand it.
Some topics in physics are easy to model and get a closed formula but some are not. In particular, fluids flow and heat flow are very difficult (if the system is not very symmetric).
To make an industrial heat exchanger, the chemical engineers use "books" that have a lot of examples for different chemical products and different geometrical configurations and try to find the more similar to get some experimental constants. These constant can be placed in formulas to get the required size of the new heat exchanger, but are only reliable if the new one is similar to the original example.
A few yeas ago, I worked at a school and we need an experiment for a physic olympiad. We measure the cooling of a plastic cup of water in different conditions. One of the ideas was to measure the effect of a metal spoon, but in the pretesting we found out that the effect is negligible. We got the bigger difference using a thin plastic lid, the cooling time was much longer.
So, to find out the best method to cool a cup of coffee you can't use a pencil and a peace of paper. You should measure it experimentally wit a thermometer. (Perhaps a computer model simulator might work.)
And in one of the Feynman books, he was trying to see if jelly gets hard if you stir it while cooling. He waited for a freezing day, got a pan with hot jelly, something to stir and a jacket. In another book someone told him that a piece of rubber from the Challenger shuttle would become hard when cold. He got some water, ice cubes and somthing to hold the rubber to test it. So probably Feynman Feynman would get a cup of coffee, a spoon and a thermometer.
Some topics in physics are easy to model and get a closed formula but some are not. In particular, fluids flow and heat flow are very difficult (if the system is not very symmetric).
To make an industrial heat exchanger, the chemical engineers use "books" that have a lot of examples for different chemical products and different geometrical configurations and try to find the more similar to get some experimental constants. These constant can be placed in formulas to get the required size of the new heat exchanger, but are only reliable if the new one is similar to the original example.
A few yeas ago, I worked at a school and we need an experiment for a physic olympiad. We measure the cooling of a plastic cup of water in different conditions. One of the ideas was to measure the effect of a metal spoon, but in the pretesting we found out that the effect is negligible. We got the bigger difference using a thin plastic lid, the cooling time was much longer.
So, to find out the best method to cool a cup of coffee you can't use a pencil and a peace of paper. You should measure it experimentally wit a thermometer. (Perhaps a computer model simulator might work.)
And in one of the Feynman books, he was trying to see if jelly gets hard if you stir it while cooling. He waited for a freezing day, got a pan with hot jelly, something to stir and a jacket. In another book someone told him that a piece of rubber from the Challenger shuttle would become hard when cold. He got some water, ice cubes and somthing to hold the rubber to test it. So probably Feynman Feynman would get a cup of coffee, a spoon and a thermometer.
That`s why I love plastic ice cubes. Keep in the freezer for some time so the water inside will freeze and enjoy your non-watered down drinks!
I smell an episode of Mythbusters coming on.
try putting cooling heat-pipe into your hot cup of coffee - your fingers will burn instantly.
1) Find person nearby with a drink that has ice in it
2) Use spoon to extract the ice from their glass
3) Put ice in coffee
Also, you may need to threaten the person with the spoon to get the ice.
2) Use spoon to extract the ice from their glass
3) Put ice in coffee
Also, you may need to threaten the person with the spoon to get the ice.
But now you've added a non negligible amount of water to your coffee. Nothing worse in the morning than watered down coffee.
bend spoon into a u-shape and stick the other end in a cup of liquid nitrogen
I once heard a tea master say that every time you pour the water from one cup to another, it cools down by 10 degrees (celsius). I'm not sure I fully believe him because pouring the water between cups 10 times didn't freeze the water. ;-)