for( i= 1,100 )
{
if( i%3==0 ) { print( 'Fizz' ) }
if( i%5==0 ) { print( 'Buzz' ) }
print( '\n' )
}
There's no need to treat FizzBuzz as a special case, as if the number is divisible by both it will have already met the conditions of the previous two statements.
...as in "you make your own luck".