Longest and Shortest Type Name in .NET 4.0 using LINQ(dotnetcurry.com)
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Longest and Shortest Type Name in .NET 4.0 using LINQ
http://www.dotnetcurry.com/ShowArticle.aspx?ID=535
2 comments
It would be pretty cool to try to instantiate each one, and then do a sizeof(instance) on it to see how large the memory footprint is.
If you only want the size of the object itself -- not the things it references -- then you don't actually need to instantiate them to know this. You can reflect on the fields of the type and calculate its memory footprint that way.
I love F#.
Same code in F# (one line, of course!)
Same code in F# (one line, of course!)
let currentNetTypes = System.AppDomain.CurrentDomain.GetAssemblies() |>
Seq.filter(fun x->x.FullName.Contains("Version=4.0.0.0")) |>
Seq.map(fun x->x.GetExportedTypes()) |> Seq.concat |>
Seq.sortBy(fun x->x.Name.Length);;
C# in one line (though I do love F#)
var currentNetTypes = from a in System.AppDomain.CurrentDomain.GetAssemblies()
from y in a.GetExportedTypes()
where a.FullName.Contains("Version=4.0.0.0")
orderby y.Name.Length
select y;
var currentNetTypes = from a in System.AppDomain.CurrentDomain.GetAssemblies()
.Where(x => x.FullName.Contains("Version=4.0.0.0"))
from y in a.GetExportedTypes()
orderby y.Name.Length
select y;The only thing I'm not overly fond of is the repeated "fun x -> x". It'd be nice if there was a way to refer to members without an instance reference. So you could write:
Seq.map ($GetExportedTypes()) |> Seq.sortBy $x.Name.Length
In Nemerle (another ML dialect for .NET), you can use _ to that end. Syntax for local functions/lambdas, all equivalent (but suited for different situations, syntactically speaking):
def foo(x) { x + 5 }
fun(x) { x + 5}
(x) => x + 5
lambda x -> x + 5
_ + 5
Or in IronPython:
currentNetTypes = sorted(
sum(
list(asm.getExportedTypes())
for asm in System.AppDomain.CurrentDomain.GetAssemblies()
if 'Version=4.0.0.0' in asm.FullName),
lambda a, b: cmp(len(a.Name), len(b.Name))
)