tika · HackerTrans

10 anni fadiscuss

271 is rather small. Which means this fake prime was quite easy to generate.

10 anni fadiscuss

:D

10 anni fadiscuss

Yes, but 1/2^80 is ridiculously large compared to 1/2^1024.

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"There are 2^1024 - 2^1023 = 9.0e307 1024-bit numbers"

This is the count of 1023 bits numbers [(x - x/2) = x/2]. 0 is a valid leftmost digit.

10 anni fadiscuss

2^1024 is a lot larger than 2^80. The implication is clear.

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