PROVE: 0 0 0 0 = 24
9 comments
Rarely have I seen a question that would cause me to leave an interview unfinished. This one would do that.
(0! + 0! + 0! + 0!)! = 24
Well there are 24 different possible combinations - assuming the 0's are different
4 * 3 * 2 * 1 = 24
is this incorrect for me to use this as a solution?
edit:
http://news.ycombinator.com/item?id=3550753
This is what I was trying to convey - I guess he's the big winner!
4 * 3 * 2 * 1 = 24
is this incorrect for me to use this as a solution?
edit:
http://news.ycombinator.com/item?id=3550753
This is what I was trying to convey - I guess he's the big winner!
[deleted]
Would HR be able to judge if the answer was right or wrong?
[deleted]
(((0!)+(0!))^((0!)+(0!)))!
=(2^2)!
=4!
=24
!(0^(0^(0^0))) = 24 ; if you believe 0^0 is 1 that is...
That's not true even under your assertion
0^0 = 1
0^(0^0) = 0^1 = 0
0^(0^(0^0)) = 0^0 = 1
!(0^(0^(0^0))) = 1! = 1Indeed. Oops
Question asked by Company's HR to my Friend..