chnuschper·vor 13 Jahren·discussIt's y=(sqrt(x) - 1)^2Consider the function l(t) which gives the appropriate line function f(x) for the line going through (t,0). The function we are looking for can then be defined as c(x) := max(l(t)(x), t in (0;1]). Just solve for t and pop it into l(t), et voila.
Consider the function l(t) which gives the appropriate line function f(x) for the line going through (t,0). The function we are looking for can then be defined as c(x) := max(l(t)(x), t in (0;1]). Just solve for t and pop it into l(t), et voila.