You Can't JavaScript Under Pressure(toys.usvsth3m.com)

  n===+n && n===(n|0)

  // i will be an array, containing integers and/or arrays like itself.
  // Sum all the integers you find, anywhere in the nest of arrays.

    return i.reduce(function(prev, next) {
        if (typeof(next) == "object" && next.length) { return arraySum(next) + prev; }
        if (typeof(next) == "number") { return next + prev; }
        return prev;
    }, 0);

      function arraySum(i) {
	var total = 0
	for(var x=0; x < i.length; x++) {
		if(typeof i[x] == 'object') {
			 arraySum(i[x])
		} else if(typeof i[x] == 'number') {
			total += i[x]
		}
	}
	return total
     }